Using
if exists window ...
instead of
if visible of window ...
is logically equivalent and does work correctly, so I'll use it.
I can't help but wonder what could be intended of a property that
always returns true?
On Nov 6, 2006, at 5:11 PM, kai wrote:
On 6 Nov 2006, at 15:40, Luther Fuller wrote:
My script said ...
set appSup to (path to application support from user domain) as
alias
...
else if visible of window of folder "Folder Name" of appSup then
my doSomeStuff()
dnd if
but other parts of the script were not working properly. Finally,
I found the problem and wrote this to fix the it ...
set appSup to (path to application support from user domain) as
alias
...
else
try
visible of window of folder "Folder Name" of appSup
if the result then my doSomeStuff()
end try
end if
It seems that 'visible of window ...' requires the window to be
visible in order to return a boolean result, otherwise it errors.
Illogical!
I'm not sure that I'd use this test to achieve what (I think)
you're after, Luther.
The visible property of an open Finder window is always true. As
you've found, an attempt to get the visible property of an unopened
Finder window will fail. Specifically, it results in an Apple Event
failure: error number -10000 ["The window must be opened to get
this property."]
An existence test might therefore be more appropriate for your
purposes:
----------
set appSup to path to application support from user domain
tell application "Finder"
if exists window of folder "Folder Name" of appSup then my
doSomeStuff()
end tell
