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Shell grep help - how to get only first occurrence of match?



I have been trying really hard to find the proper grep syntax for what I
guess is really simple, but I just can't get it right

The text I like to grep is made up of two or more columns numbers separated
by one or more spaces. The following columns may consist of any combination
of numbers and characters .

What I need to do is to get only the first column, which unfortunately may,
or may not, begin with spaces, like this:

   12345    647890   kdghjblrttrep 9845698476 lkjlfkdj

So by writing 

grep "^[0-9]*" -o 

I get all the first columns of those lines that doesn't begin with spaces,
but if I try to include one of more spaces like this

grep  "^ *[0-9]*"  -o

it gives my all columns containing numbers, besides what I really want is
the numbers of the first columns but without the spaces

Can anyone please help ?



-------------------------------------------------
Richard Rönnbäck
Publishing-konsult
email@hidden
Helsingörsgatan 24
164 44 KISTA
SWEDEN
+46 (0) 8 444 06 08
+46 (0) 70 774 06 08
-------------------------------------------------


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References: 
 >Re: Shell script help - get date of last modified file in hierarchy (From: "Mark J. Reed" <email@hidden>)



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