Thread-topic: Shell grep help - how to get only first occurrence of match?
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Thank you all!
I decided to use awk, but the other suggestions will also come in handy for
the project I am working on so this was even more helpful than I expected
:-)
Thanks again!
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Richard Rönnbäck
Publishing-konsult
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> Från: Walter Bushell <email@hidden>
> Datum: Wed, 28 Mar 2007 22:02:36 -0400
> Till: "email@hidden :applescript users"
> <email@hidden>
> Ämne: Re: Shell grep help - how to get only first occurrence of match?
>
> The man pages were written for people who already know what the
> commands For "awk" this is more true than most Eunichs commands..
>
>
> On Mar 28, 2007, at 8:18 PM, Malcolm Fitzgerald wrote:
>
>>
>> On 29/03/2007, at 3:57 AM, Mark J. Reed wrote:
>>
>>> If you have columns of data separated by arbitrary amounts of
>>> whitespace, the command you're looking for is awk, rather than grep.
>>>
>>> awk '{print $1}' will print the first column of every line. $2 for
>>> the second, etc.
>>> $NF (short for "Number of Fields") for the last column, $(NF-1) for
>>> the second-to-last, etc.
>>> $0 is the whole line.
>>>
>>> you can stick /pattern/ in front of the {...} block to run it only
>>> for
>>> lines matching that pattern, e.g.
>>>
>>> awk '/[0-9]/ {print $1}' will print the first column of all lines
>>> that contain a digit anywhere in the line. Note that this means
>>> it is
>>> never necessary to do grep | awk. :)
>>
>>
>> Wow, it's that easy. You wouldn't know it from the man page.
>>
>> malcolm
>>
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