According to the rules for operator precedence, the pointer is being
incremented and then it is de-referenced. In other words, the routine does
nothing useful.
Try:
(*number)++;
Greg
On 2/28/06 12:30 PM, "Mark Williams" <email@hidden> wrote:
> Ok I am trying something like the following:
>
> -(BOOL)numberAdded:(int*)number
> {
> *number++;
> return YES;
> }
>
> -(void)addNumber
> {
> int flct = 0;
>
> [self numberAdded:&flct];
>
> NSLog(@"%i",flct);
> }
>
> and basically it is not adding one to the number. How do I pass a
> pointer to an integer so that I can modify it in another function? I
> thought I had it right but clearly I do not.
>
>
> Mark.
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