#!/usr/bin/env bash
if [ ! -f "socket file that X11 creates in /tmp" ]; then
open /Applications/X11.app
fi
export DISPLAY=:0
exec whatever
On Jul 18, 2007, at 7:04 AM, Dave Williss wrote:
I'm trying to find a way to have an X11 application start X11.app
if it's not already running.
For the most part, something like this works pretty well...
* look for the socket file that X11 creates in /tmp. If not
there, skip the next step
* call XOpenDisplay. If that works, X11 is running - nothing to do.
* find /Applications/Utilities/X11.app/Contents/MacOS/X11
* call execp() or system() to start it.
* call XOpenDisplay again
This has been working fine in most versions on Mac OS. However,
launching X11 this way isn't working with the version of X11 from
the latest beta OS. The X11 icon never shows up as having started
in the task bar and the server never starts, but X11.app obviously
did *something* because the console log reports that an xterm was
unable to connect to the X server.
This is only a problem if I launch it via calls to execp() or system
(). If I launch it from a command shell it works just fine.
I don't know for sure if it's the X11.app that's causing the
problem or the OS itself. Maybe by using system() I'm bypassing
some vital thing. I'm wondering if there's a more accepted way
under OS X to have one program launch another.
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--
✐The primary task of most software projects is to discover and
resolve these unknowns rather than to build a system. -- Philip G.
Armour
--
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✇ Lawrence Livermore National Laboratory
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(opinions expressed herein are mine and not those of LLNL)
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