Re: Hidden Overloaded C++ Virtual Function

Subject: Re: Hidden Overloaded C++ Virtual Function

From: Adin Hunter Baber <email@hidden>

Date: Sat, 31 Dec 2005 07:56:56 -0600

Delivered-to: email@hidden

On 2005 Dec 30, at 1:12 PM, Nick Nallick wrote:

There's probably something subtle here that I don't understand, but can somebody tell me why gcc4 is telling me that A::foo(a) is hidden by B::foo(b) when I comment out B::foo(a) below? This seems like an overenthusiastic warning to me.

Thanks,
Nick

warning: 'virtual void A::foo(a)' was hidden
warning: by 'virtual void B::foo(b)'

struct a
{
int i;
};

struct b
{
double x;
};

class A
{
virtual ~A() {};
virtual void foo(a) {};
virtual void foo(b) {};
};

class B : public A
{
// virtual void foo(a) {};
virtual void foo(b) {};
};

Others have pointed out why you are having a problem. Here's away to avoid the problem:

class A

{

public:

virtual ~A();

void foo(a);

void foo(b);

private:

virtual void foo_a_impl(a);

virtual void foo_b_impl(b);

};

void A::foo(a)

{

foo_a_impl(a);

}

void A::foo(b)

{

foo_b_impl(b);

}

class B

{

public:

// ...

private:

virtual void foo_a_impl(a);

virtual void foo_b_impl(b);

};

Class B will inherit the public foo()'s, and will automatically call the correct private virtual implementation functions. You no longer need to worry about the hidden functions issue.

Adin Hunter Baber

email@hidden

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References:

>Hidden Overloaded C++ Virtual Function (From: Nick Nallick <email@hidden>)