Here, _Parameter(__value, __name) - far as I can tell - is one of
many
structure constructors, and thus should NOT return any value !!!
I'm not a C++ syntax expert, but I think you're misunderstanding what
this does -- that's not a literal constructor call (as in this-
>_Parameter()) but a class name used in object creation (which of
course does call a constructor).
I know in our code we end up with stuff like
this->notify(String("foo"));
which makes a temporary String object and passes it to the notify
method.
So presumably in the code you question a _Parameter is created and
then operator= is called.
David Dunham A Sharp, LLC
Voice/Fax: 206 783 7404 http://a-sharp.com
"People seem to misinterpret complexity as sophistication" -- Niklaus
Wirth
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