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((b - theDate) div -2500000 + 1 )
Which takes the difference (in seconds) between the current date and and the the same day in January, divides that by 289 days (in seconds) and adds a month. This gives you the current month, roughly. This will probably work fine but I'd worry about it being correct under all circumstances.
| References: | |
| >Re: getting the date (From: Nigel Garvey <email@hidden>) | |
| >Re: getting the date (From: Walter Ian Kaye <email@hidden>) | |
| >Re: getting the date (From: Graff <email@hidden>) |
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