kai wrote on Thu, 20 Oct 2005 23:12:31 +0100:
>... Of course, if anyone's into using atypical parent properties,
>it might be safer to refer to AppleScript, rather than to the script
>itself:
>property parent : 3 (* Or: {"a", "b"}, October, pi, etc. *)
>tell "1 1 1" to tell (my date it) to it
>--> error number -1728 (errAENoSuchObject): Can't get date "1 1 1" of
>[whatever].
"Hello, list. I've written the above script and it doesn't work. Can
anyone tell me what I'm doing wrong?" ;-)
>on requiredMonth()
>> tell "1 1 1" to tell (my date it) + 24 * days to tell {it + ¬
>> 7 * days, date string's words & "1", 1} to considering case
>> set end to beginning's date string's words
>> repeat while end's item item 3 is in item 2
>> set item 3 to (item 3) + 1
>> end repeat
>> set end to {item 2's item item 3, end's item item 3}
>> repeat 10 times
>> set beginning's day to 32
>> set end's end to beginning's date string's word item 3
>> end repeat
>> its end
>> end considering
>> tell (choose from list result) to if it is false then
>> error number -128
>> else
>> my date beginning's month
>> end if
>end requiredMonth
The above code (by me), while it is to be avoided in its own right, might
not work properly if your word for "January" or "February" is the same as
your word for "Thursday". Fortunately, in western languages, any
coincidence is more likely to affect "March" and "Tuesday", which is no
problem here. :-)
>on totalHours for m from h
> tell (current date)
> set its month to m
> set day to 28
> tell {it + 4 * days, its weekday as integer, ((h's item ¬
> 1) + (h's item 2) + (h's item 3) + (h's item 4) + ¬
> (h's item 5) + (h's item 6) + (h's item 7)) * 4}
> repeat with d from item 2 to (item 2) + ((beginning - ¬
> (beginning's day) * days)'s day) - 29
> set last item to end + (h's item (d mod 7 + 1))
> end repeat
> its end
> end tell
> end tell
>end totalHours
>
>totalHours for requiredMonth() from {0, 2.5, 2.5, 2, 0, 2, 0}
I can imagine Ronnie Barker reciting this at high speed from memory. :-)
NG
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