Re: Stripping modifier keys

Subject: Re: Stripping modifier keys

From: Michael Grady <email@hidden>

Date: Wed, 20 Jun 2007 11:08:17 -0700

Delivered-to: email@hidden

Marco,

you'll want to look at the new TextInputSource (TIS) API avaiiable in Leopard HIToolbox (TextInputSources.h). The TIS API supercedes the deprecated KL API and will be available in 64bit. Hope the following snippet helps:

TISInputSourceRef kbInputSourceRef = (TSMInputSourceRef) TISCopyCurrentKeyboardLayoutInputSource();

// Get the 'uchr' data

CFDataRef uchrDataRef = (CFDataRef)TISGetInputSourceProperty( kbInputSourceRef, kTISPropertyUnicodeKeyLayoutData );

Boolean existsUchr = ( (uchrDataRef != NULL) && (CFDataGetBytePtr(uchrDataRef) != NULL) && (CFDataGetLength(uchrDataRef) != 0) );

if (existsUchr) {

UInt32 modifiers = 0; // If you're getting this from a CarbonEvent, you'll want to right-shift... i.e., modifiers >> 8 below

UInt32 deadKeyState = 0;

UniChar *uCharsOut = malloc( ... );

UniCharCount numUCharsOut;

OSStatus status = UCKeyTranslate( (const UCKeyboardLayout *)CFDataGetBytePtr( uchrDataRef ),

keyCode, kUCKeyActionDown,

modifiers, LMGetKbdType(), kUCKeyTranslateNoDeadKeysMask /*or kNilOptions*/,

&deadKeyState, maxUnicodeStrLength, &numUCharsOut, uCharsOut );

}

CFRelease(kbInputSourceRef);

Michael Grady

On Jun 20, 2007, at 8:36 AM, Marco Piovanelli wrote:

When the user enters some modifier+key combinations, I'd

like to find out what string of UniChars would have been

generated if no modifiers had been used.

Is there a way to do this in a future-compatible way without

resorting to a combination of KLGetCurrentKeyboardLayout,

KLGetKeyboardLayoutProperty, UCKeyTranslate and KeyTranslate,

which seems pretty convoluted for a simple task like this?

TIA,

-- marco

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Re: Stripping modifier keys
- From: "Marco Piovanelli" <email@hidden>

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>Stripping modifier keys (From: "Marco Piovanelli" <email@hidden>)