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Re: Absolute Value |x - y|

Subject: Re: Absolute Value |x - y|
From: Frederick Cheung <email@hidden>
Date: Sun, 5 Dec 2004 03:11:11 +0000
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On 4 Dec 2004, at 20:56, Gregory Weston wrote:

On Dec 4, 2004, at 2:18 PM, Malte wrote:

i've been looking around trying to find a method that calculates the
|absolute value| of a number.
Without success.
Does anyone know if such a function exists?


They do, but you're probably better off just writing

T abs = ((x<y) ? (y-x) : (x-y));

where T is whatever type you need the result to be.

The difference is probably that fabs has well defined behaviour in case one (or both) of x and y is something like NaN or +/- \infty, whereas this might not be the case for the expression you give.

Fred

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