I came up with a similar solution, but different:
I prepend the string (Note that I just add "1" in the format itself)
NSString* theString = [NSString stringWithFormat:@"1%0.4lf", aValue];
theString = [theString stringByTrimmingCharactersInSet:...
// Where we differ is that I now use substringWithRange:
short len = [theString length];
theString = [theString substringWithRange:NSMakeRange(1, len-1)];
// I then apply the removal of the decimal separator
return [theString stringByTrimmingCharactersInSet:[NSCharacterSet
characterSetWithCharactersInString:(NSString *)[[NSUserDefaults
standardUserDefaults] objectForKey:NSDecimalSeparator]]];
Does anyone know which one might be better--i.e., is substringWithRange (+
the length call) costlier than stringByTrimmingCharactersInSet or is it the
other way around?
Thanks!
Mark
> From: Ricky Sharp <email@hidden>
> After thinking about this a bit more, you could still use
> stringByTrimmingCharactersInSet, but first modify your string such that
> it won't trim from the left. For example, prefix it with say 'A'.
> After your trimming, remove that 'A'.
>
> - (NSString*)stringWithFormattedFloat:(float)aValue
> {
> NSString* theString = [NSString stringWithFormat:@"%0.4lf", aValue];
>
> theString = [NSString stringWithFormat:@"A%@", theString];
>
> theString = [theString stringByTrimmingCharactersInSet:
> [NSCharacterSet characterSetWithCharactersInString:@"0."]];
>
> theString = [theString stringByTrimmingCharactersInSet:
> [NSCharacterSet characterSetWithCharactersInString:@"A"]];
>
> return theString;
> }
>
> This appears to work. Note that "0" will become the empty string, but
> you mentioned that you already handle that special case. And of course
> replace the hard-coded values with proper decimal separator.
>
> ___________________________________________________________
> Ricky A. Sharp mailto:email@hidden
> Instant Interactive(tm) http://www.instantinteractive.com
>
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