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Re: Array of random, non-repeating numbers




On 13/07/2006, at 19:39, Michael Ash wrote:

On 7/13/06, Bobby B <email@hidden> wrote:
Hey guys,

I'm trying to write a way to generate a random array of X numbers, and
the numbers need to be between 0 and X, and not be repeating (its for
generating a random playlist.)

Just generate the random playlist directly, don't bother with indexes. Put the tracks into an array, then use the canonical shuffle algorithm which, in pseudocode, is:

for i from 0 to array_length - 2
  random_index = random in [i, array_length - 1]
  swap array[i] with array[random_index]

Transforming this into real code is left as an exercise for the reader.

Here:

@interface NSMutableArray (Shuffling)
- (void)shuffle;
- (void)swapObjectAtIndex:(unsiged)a withObjectAtIndex:(unsiged)b;
@end

@implementation NSMutableArray (Shuffling)
- (void)shuffle
{
	int max = [self count] -1;
	int i;
	for (i = 0; i < max; i++) {
		int choice = random() % max;
		[self swapObjectAtIndex:i withObjectAtIndex:choice];
	}
}
- (void)swapObjectAtIndex:(unsiged)a withObjectAtIndex:(unsiged)b
{
	id temp = [self objectAtIndex:a];
	[self replaceObjectAtIndex:a withObject:[self objectAtIndex:b]];
	[self replaceObjectAtIndex:b withObject:temp];
}
@end


Best Regards,

Nir Soffer

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References: 
 >Array of random, non-repeating numbers (From: "Bobby B" <email@hidden>)
 >Re: Array of random, non-repeating numbers (From: "Michael Ash" <email@hidden>)



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