Re: C++ question: dynamic

int main (int argc, char * const argv[]) {

A *aa = static_cast<A *>(getA());

A *ba = static_cast<A *>(getB());

if(typeid(A) == typeid(*aa)) {

cout << "aa IS A (" << typeid(*aa).name() << ")" << endl;

} else {

cout << "aa ISN'T A (" << typeid(*aa).name() << ")" << endl;

}

if(typeid(A) == typeid(*ba)) {

cout << "ba IS A (" << typeid(*ba).name() << ")" << endl;

} else {

cout << "ba ISN'T A (" << typeid(*ba).name() << ")" << endl;

}

return 0;

}

works just as I expected:

[Session started at 2008-07-13 22:33:04 -0400.]

aa IS A (1A)

ba ISN'T A (1B)

On Jul 13, 2008, at 7:37 PM, Dmitry Markman wrote:

Hi, all

I accidentally encountered the following code (not exactly of course that is very simplified version)

class V {
virtual int getID() = 0;
};

class A : public V {
public:
virtual int getID(){return 0;}
virtual int getIDA(){return 10;}
};

class B : public V {
public:
virtual int getID(){return 1;}
virtual int getIDB(){return 11;}
};

A *a = new A();
B *b = new B();

void *getA() {
return a;
}

void *getB() {
return b;
}

int main (int argc, char * const argv[]) {
A *sa = static_cast<A *>(getB());
A *aa = dynamic_cast<A *>(sa);
//here aa ISN'T NULL!!!!!

   return 0;
}

in that fragment
aa isn't null
I'd expect NULL, of course
NOTE: gdb clearly shows that aa (or sa) is an instance of the B class (with set print object on and set print vtbl on)
(gdb) p aa
$2 = (B *) 0x106940
(gdb) p *aa
$3 = (B) {
<V> = {
_vptr$V = 0x2078
}, <No data fields>}
(gdb)

from other hand
the following code behaves just fine

int main (int argc, char * const argv[]) {
  V *v = static_cast<V *>(getB());
  A *aa = dynamic_cast<A *>(v);
//here aa IS NULL which is good

   return 0;
}

thanks in advance for any help with clarification

Dmitry Markman

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References:
	>C++ question: dynamic_cast (From: Dmitry Markman <email@hidden>)

Re: C++ question: dynamic_cast