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Nathan --
I'm opening the raw device; the whole media. I need the 2352 B blocks because I'm reading VCDs.
So, you're saying that there's probably nothing I can do to speed it up on my machine, but that it might go faster on other machines. That's what I needed to know... Thanks!
This type of thing is very drive dependent. It depends heavily on drive firmware, especially when bad blocks are encountered, when media is scratched, smudged, or imbalanced, etc.
| References: | |
| >Re: reading a CD-ROM quickly... (From: Chris Sarcone <email@hidden>) |
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