Re: Sorting XML using XSL loading the xml string

I am queirying a server and getting a returned xml string within in a soap wrapper.  I have done some searching and found that I can then sort the data using and XSL style sheet.  

My problem is this, I am trying to load both my xml string and then the xsl string and do the transformNode then return the sorted xml and display it in my widget.

I keep getting the undefined value _javascript_ error about my loaded xml string.  Here is the code:

=======================

I pass in the xml string and the debug displays it fine.

function sortXML(xmlDoc){

DEBUG("the passed xml is " + xmlDoc);

var myXSLtemplate = "<<?xml version='1.0'?>\n\

<xsl:stylesheet xmlns:xsl=\"http://www.w3.org/TR/WD-xsl\">\n\

<xsl:template match=\"/\">\n\

    <table border=\"2\" bgcolor=\"yellow\">\n\

      <tr>\n\

        <th>Title<\/th>\n\

        <th>Artist<\/th>\n\

      <\/tr>\n\

      <xsl:for-each select=\"CATALOG/CD\" order-by=\"+ ARTIST\">\n\

      <tr>\n\

        <td><xsl:value-of select=\"TITLE\"/><\/td>\n\

        <td><xsl:value-of select=\"ARTIST\"/><\/td>\n\

      <\/tr>\n\

      <\/xsl:for-each>\n\

    <\/table>\n\

<\/xsl:template>\n\

<\/xsl:stylesheet>";

// Load XML

var xml;

xml.load(xmlDoc);   HERE IS WHERE THE _javascript_ ERRORS "undefined value"

// Load the XSL

var xsl;

xsl.load(myXSLtemplate);

// Transform

var sortedXML = xml.transformNode(xsl);

return sortedXML;

}

======================

Any help is appreciated.

Mark

Mark Spidle

Assistant Manager of Information Systems

515-457-5873

email@hidden

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