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Re: Regular expression problem



Try regex.replaceAll(var, "\\\\1");

Cheers
Filip

On Jan 28, 2008, at 8:59 PM, "D.K. Johnston" <email@hidden> wrote:

I'm trying to construct a regular expression with this:

   regex = regex.replaceAll( var, "\\1" );

But it puts only 1 in place of var in the string, not \1. I can't understand what I'm doing wrong. The preceding line:

   regex = regex.replaceFirst( var, "([abc])" );

works just fine.

dkj
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 >Regular expression problem (From: "D.K. Johnston" <email@hidden>)



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