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Re: inline assembly in gcc not working (was Shared Memory )

Subject: Re: inline assembly in gcc not working (was Shared Memory )
From: Jonas Maebe <email@hidden>
Date: Mon, 4 Oct 2004 20:27:52 +0200
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On 4 okt 2004, at 19:51, Marc Colosimo wrote:

volatile unsigned char  *testB;
int main(void) {
testB = (unsigned char *) malloc(sizeof(unsigned char));

This is wrong. lwarx/stwcx work on word-sized entities. You are only allocating a byte.

*testB = 0; printf("testB is %d and stored at %d.\n Now locking.\n", *testB, (int) testB); _lock_(testB); printf("testB is now %d\n", *testB);

It's normal that this prints 0, since you are on a big-endian system. The byte at test+3 has been incremented by one (and depending on its previous value, possibly also the bytes at test+2 and test+1 and in the extreme case also at test).

   	 return 0;
}

Jonas

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Follow-Ups:
- Re: inline assembly in gcc not working (was Shared Memory )
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References:
	>Re: Shared Memory (Semaphore and mutex) (From: Marc Colosimo <email@hidden>)
	>Re: Shared Memory (Semaphore and mutex) (From: Shaun Wexler <email@hidden>)
	>Re: Shared Memory (Semaphore and mutex) (From: Marc Colosimo <email@hidden>)
	>Re: Shared Memory (Semaphore and mutex) (From: Shaun Wexler <email@hidden>)
	>inline assembly in gcc not working (was Shared Memory ) (From: Marc Colosimo <email@hidden>)

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