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Re: Handling Session timeout with ajax
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Re: Handling Session timeout with ajax



On 27/01/2009, at 1:10 PM, Chuck Hill wrote:


On Jan 26, 2009, at 5:25 PM, Paul Hoadley wrote:

On 27/01/2009, at 7:55 AM, Chuck Hill wrote:

Should this also work in Application.handleException()? I've got this:

public WOResponse handleException(Exception anException, WOContext aContext) {
AMErrorPage errorPage = (AMErrorPage) pageWithName(AMErrorPage.class
.getName(), aContext);
errorPage.setPageType(AMErrorPage.EXCEPTION);
if (AjaxUtils.isAjaxRequest(aContext.request())) {
AjaxUtils.redirectTo(errorPage);
return errorPage.context().response();
}
return errorPage.generateResponse();
}


Throwing an exception from an Ajax action bypasses my AMErrorPage, somehow logs me out of the app, and returns my Main page. I can't even see how it's occurring. There's literally nothing in the console beyond a log message from AMErrorPage.setPageType(). Again, this is a slightly different issue than the OP, and I assume your code above was for Application.handleSessionRestorationErrorInContext.

I have the same code (more or less) and it worked the last time that I tested it. It sounds like there might be some other request getting to the app after the one causing the exception. Try overridding dispatchRequest and logging out each request.uri().

Looks like there is:

Jan 27 11:49:24 AM[54210] WARN NSLog - <er.ajax.AjaxRequestHandler>: Exception occurred while handling request:
java.lang.NullPointerException
Jan 27 11:49:24 AM[54210] INFO NSLog - Application.handleException: Handling an Exception:
[2009-1-27 11:49:24 CST] <WorkerThread1> java.lang.NullPointerException


... [Stack trace of my deliberately-generated NPE deleted]

Unrelated, but you can do this more cleanly with

NSLog.out.appendln(new RuntimeException("backtrace"));
or
new RuntimeException("backtrace").printStackTrace();


Jan 27 11:49:24 AM[54210] INFO NSLog - AMErrorPage.setPageType: pageType = exception
Application.dispatchRequest: URI = /cgi-bin/WebObjects/AM.woa/wo/5.0


That looks unusual (to me).


The thing to do now is to look in that page for something (form, input, link, JavaScript) with that URL. Then try to figure out why that is sending a request after the exception.

I can't find it anywhere. It's not on the page where the exception was generated, and I've pared down AMErrorPage to essentially nothing. I've searched with Safari's Web Inspector which apparently looks in the source, the DOM and loaded resources.


Can you think of another way I can track this down?


-- Paul.

w  http://logicsquad.net/
h  http://paul.hoadley.name/


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References: 
 >Handling Session timeout with ajax (From: Amedeo Mantica <email@hidden>)
 >Re: Handling Session timeout with ajax (From: Chuck Hill <email@hidden>)
 >Re: Handling Session timeout with ajax (From: Paul Hoadley <email@hidden>)
 >Re: Handling Session timeout with ajax (From: Chuck Hill <email@hidden>)
 >Re: Handling Session timeout with ajax (From: Paul Hoadley <email@hidden>)
 >Re: Handling Session timeout with ajax (From: Chuck Hill <email@hidden>)



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