Re: How can I get the maximum shared memory segment size in program?
site_archiver@lists.apple.com Delivered-To: darwin-dev@lists.apple.com On Dec 28, 2007, at 21:34 , bady yu wrote: By the way, my system is Leopard. Justin -- Justin C. Walker, Curmudgeon-At-Large Institute for the Absorption of Federal Funds -------- Men are from Earth. Women are from Earth. Deal with it. -------- _______________________________________________ Do not post admin requests to the list. They will be ignored. Darwin-dev mailing list (Darwin-dev@lists.apple.com) Help/Unsubscribe/Update your Subscription: http://lists.apple.com/mailman/options/darwin-dev/site_archiver%40lists.appl... I can use "sysctl kern.sysv.shmmax" or "ipcs -M" to get the integer (4194304). But they are both command line tools. It is not convenient to call it inside the problem. I also have tried to use the sysctlbyname system call: sysctlbyname ("kern.sysv.shmmax", &shmmax, &len, NULL, NULL). Although this call return 0, the shmmax variable does not hold the correct value. Can anybody tell me an appropriate way? Thank you in advance! 'sysctl(1)' just uses 'sysctl(2)'. Check the man page ("man 2 sysctl") and the source for 'sysctl(1)' available on Apple's Darwin website (the 'system_cmds-431' project, for 10.5). This email sent to site_archiver@lists.apple.com
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Justin C. Walker