5 Feb
2002
5 Feb
'02
4:31 p.m.
On Tue, 5 Feb 2002, Justin C. Walker wrote:
Given that, the call, per se, does not 'hose the kernel'; it just stops
processing. It should print the character string you pass it, and then
grind ot a halt. The fact that it doesn't is a bit odd. Maybe you (he)
mentioned this, but I've lost it: is this call in a kext? Is it just
supposed to call IOPanic()?
And another (gross) thought: what happens if you trigger a panic indirectly, e.g. mypanic(char *message) { float k; printf(message); k /= 0; } Does that panic (more) correctly for you? David --------------------------------------------------------------------- Check out my weekly web comic: http://www.techmagazine.org