Shell grep help - how to get only first occurrence of match?
Shell grep help - how to get only first occurrence of match?
- Subject: Shell grep help - how to get only first occurrence of match?
- From: Richard Rönnbäck <email@hidden>
- Date: Wed, 28 Mar 2007 17:53:54 +0200
- Thread-topic: Shell grep help - how to get only first occurrence of match?
I have been trying really hard to find the proper grep syntax for what I
guess is really simple, but I just can't get it right
The text I like to grep is made up of two or more columns numbers separated
by one or more spaces. The following columns may consist of any combination
of numbers and characters .
What I need to do is to get only the first column, which unfortunately may,
or may not, begin with spaces, like this:
12345 647890 kdghjblrttrep 9845698476 lkjlfkdj
So by writing
grep "^[0-9]*" -o
I get all the first columns of those lines that doesn't begin with spaces,
but if I try to include one of more spaces like this
grep "^ *[0-9]*" -o
it gives my all columns containing numbers, besides what I really want is
the numbers of the first columns but without the spaces
Can anyone please help ?
-------------------------------------------------
Richard Rönnbäck
Publishing-konsult
email@hidden
Helsingörsgatan 24
164 44 KISTA
SWEDEN
+46 (0) 8 444 06 08
+46 (0) 70 774 06 08
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