Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
- Subject: Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
- From: Steve Bird <email@hidden>
- Date: Thu, 17 Jun 2004 13:07:10 -0400
On Jun 17, 2004, at 11:38 AM, Uwe Jagoda wrote:
hello folks,
maybe this is trivial - but not for me. From time to time i ask myself:
What's behind the curtain ?
sin(4*pi^2*t) 0 >= t <= pi/3
AS WRITTEN, it's nonsensical.
I suspect it should be:
sin(4*pi^2*t) 0 <= t <= pi/3
Which means to evaluate the expression "sin(4*pi^2*t)" for all values
of "t" between 0 and pi/3, inclusive.
----------------------------------------------------------------
Steve Bird
Culverson Software - Elegant software that is a pleasure to use.
www.Culverson.com (toll free) 1-877-676-8175
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