Re: Converting *u unicode hex sequences
Re: Converting *u unicode hex sequences
- Subject: Re: Converting *u unicode hex sequences
- From: Deborah Goldsmith <email@hidden>
- Date: Mon, 05 Nov 2007 18:38:11 -0800
If you are running on 10.4 or later, you can use CFStringTransform.
CFStringTransform(myMutableString, range, CFSTR("Hex-Any"), NO);
"Hex-Any" is equivalent to "Hex-Any/Java", and the \u style is the one
used in Java.
Deborah Goldsmith
Internationalization, Unicode Liaison
Apple Inc.
email@hidden
On Nov 4, 2007, at 7:12 PM, email@hidden wrote:
Hello list.
My code receives NSStrings containing unicode hex escapes that start
with asterisk (*) instead of backslash (\), and I need to decode
these strings. For example, I need to convert @"hello*u0020world"
to @"hello world".
Using NSMutableString replaceOccurrencesOfString:withString:range:
to convert @"*" to @"\\", yields @"hello\u0020world" as expected,
but I can't seem to get from there to @"hello world".
I realize that \u0020 is neither percent-escaped nor UTF-8 encoded.
I've tried searching this list's archives, and the web in general,
all tried the variants of
stringByReplacingPercentEscapesUsingEncoding: and
stringWithCString:encoding: I can think of. I scanned the CFString
docs, but none of the functions jumped out at me.
So, how does one convert from @"hello*u0020world" to @"hello world",
short of parsing the hex sequences?
Thanks.
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