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Re: Storing values in dictionary with their address as the key
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Re: Storing values in dictionary with their address as the key


  • Subject: Re: Storing values in dictionary with their address as the key
  • From: Andy Lee <email@hidden>
  • Date: Mon, 28 Jul 2008 15:34:27 -0400

On Jul 28, 2008, at 2:31 PM, Dave Carrigan wrote:
On Jul 28, 2008, at 11:13 AM, Carter R. Harrison wrote:

If I wanted to store an object in a dictionary and set its key as the object's memory address - how would I go about doing this?

I'm racking my brains trying to think of a good reason to do this and am drawing a blank. I can, however, think of myriad bad reasons.

Count me as another mystified person -- can you say what you're trying to do? I'm thinking maybe some kind of serialization or maybe object caching, but nothing makes sense. It sounds like what you want is a set of objects rather than a dictionary. If you have an address you can just dereference the address -- you don't need to look it up in a dictionary.


Or are you just messing around with dictionaries in general to see how they work?

[dictionary setValue:myObject forKey:[NSString stringWithFormat:@"%x", &myObject]];
}


The above does seem to work, but the memory address that I get always seems to be the same.

myObject is a variable (of type pointer) that is allocated on the stack. Its address is always going to be the same inside that tight loop, since the stack pointer isn't changing.

In other words, you don't want the & in front of myObject, which is giving you the address of a pointer variable rather than the value of the pointer.


As others have already pointed out as I typed this, you can use an NSValue instead of an NSString. But again, I can't think of a good reason to do this.

--Andy


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  • Follow-Ups:
    • Re: Storing values in dictionary with their address as the key
      • From: Quincey Morris <email@hidden>
References: 
 >Storing values in dictionary with their address as the key (From: "Carter R. Harrison" <email@hidden>)
 >Re: Storing values in dictionary with their address as the key (From: Dave Carrigan <email@hidden>)

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