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Re(2): Re(2): Re(2): Counting Words and Characters
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Re(2): Re(2): Re(2): Counting Words and Characters
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Re(2): Re(2): Re(2): Counting Words and Characters
From: "Arthur Cormack" <
email@hidden
>
Date: Fri, 13 Jul 2001 16:22:28 -0400
Sweet!!! This works.
Thank you so much.
-Arthur
email@hidden writes:
>
>Thank you Michele. This too will work, even if you don't know what
>
>word number 5 is.
>
>(... it's pretty obvious actually)
>
>... but if the pattern was not unique in the line being analysed -
>
>say, if word 5 also occurred earlier, or later on in the line ... it
>
>could cause some trouble, no? if word 1 was the same as word 5, for
>
>example, and we looked for the offset, we snip in the wrong place.
>
>Am I being too stubborn?
>
>
So, the problem is that you want to replace word five, regardless of
>
what
>
it is, and do not want to replace any other instances of that word?
>
That's even easier, and I should have done that in the second
>
iteration,
>
had I thought about it a bit longer.
>
>
set stringtochange to "The quick brown fox jumped over the dirty
>
black
>
dog's head."
>
set {tid, text item delimiters} to {text item delimiters, space}
>
set listtochange to text items of stringtochange
>
set item 5 of listtochange to "leaped"
>
set newstring to listtochange as text
>
set text item delimiters to tid
>
newstring
>
>
--Michelle
References:
>
Re: Re(2): Re(2): Counting Words and Characters
(From: Michelle Steiner <email@hidden>)
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