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Re: Why won't this parse?
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Re: Why won't this parse?


  • Subject: Re: Why won't this parse?
  • From: Bill Briggs <email@hidden>
  • Date: Thu, 10 May 2001 22:39:04 -0300

At 9:01 AM -0700 10/05/01, David Graham wrote:
I am trying to parse a Eudora nickname file to make a list of aliases. I wish I could just get this directly from Eudora through AS but it's not reliable since you can't get a recently added nickname by index ... did that make sense?

I have only read this thread just this evening, so I see that you've got the parsing problem solved, but I think you can do this directly from Eudora as you initially wanted to do with a LOT less code, if you adapt to something odd that Eudora seems to want.

I've extracted just such lists from nickname files for some of my own scripts, so I think I know where the statement "you can't get a recently added nickname by index" comes from. The odd thing about Eudora is that it appears to number indicies of nicknames like an engineer; viz. starting from zero, not 1.

I'll copy a piece of code below that gets the nickname list from a nickname file for our Mac User Group, and you'll see how the numbering works. If I were to do the "conventional" numbering in the repeat loop, then it appears to be unable to get the nickname for the last person added to the file, which is likely what you were seeing. This should solve your problem.

Eudora scripting certainly has some oddities about it, and there are bugs, but this should not give you a problem with faulty results. It has never screwed up for me.

- web


set theList to {}
tell application "Eudora"
set theCount to count of nicknames of nickname file "CNBMUG"
repeat with i from 0 to (theCount - 1) -- errors if you use 1 to theCount
set theName to nickname of nickname i of nickname file "CNBMUG"
copy theName to end of theList
end repeat
end tell
theList
--theCount -- comes to 170
--theName
--get count of theList -- comes to 170, but only if loop starts at 0


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    • Re: Why won't this parse?
      • From: David Graham <email@hidden>
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