Re: How to calculate/process this one?
Re: How to calculate/process this one?
- Subject: Re: How to calculate/process this one?
- From: Paul Berkowitz <email@hidden>
- Date: Sat, 27 Apr 2002 10:00:54 -0700
On 4/27/02 9:42 AM, "Arthur J Knapp" <email@hidden> wrote:
>
> Let's say I have a random number like 11050. Now I want to add each pair
>
> of consecutive digits to give the next line (so 11050 becomes 2155). I
>
> want to repeat this step until I have a two-digit number.
>
I don't understand, how does 11050 become 2155 ???
He's adding every single (overlapping) adjacent pair.
1 + 1 = 2 -- digits 1 and 2
1 + 0 = 1 -- digits 2 and 3
0 + 5 = 5
5 + 0 = 5
The only reason he number of digits is reduced is because of all those 0 and
1 digits keeps the individual sums less than 10. if he's started out with
99599
9 + 9 = 18
9 + 5 = 14
5 + 9 = 14
9 + 5 = 18
we now have an 8-digit number 18141418.
The next number would be 9955559. Then you'd get 181410101014. Then
9955111115. Then 181410622226. I don't think it's ever going to reduce to 1
digit, although I wouldn't like to have to prove that.
The whole idea that you could reduce the length while trying to concatenate
_additions_ which increase the numbers of digits every time he sum is
greater than 10 is - well, I'm not going to use the word that comes to mind.
--
Paul Berkowitz
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