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Re: Need XOR solution
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Re: Need XOR solution


  • Subject: Re: Need XOR solution
  • From: "Marc K. Myers" <email@hidden>
  • Date: Tue, 06 Aug 2002 22:22:57 -0400
  • Organization: [very little]

> Date: Tue, 06 Aug 2002 16:33:17 -0400
> Subject: Re: Need XOR solution
> From: "Arthur J. Knapp" <email@hidden>
> To: <email@hidden>
>
> > Date: Mon, 05 Aug 2002 18:45:28 -0400
> > From: "Marc K. Myers" <email@hidden>
> > Subject: Need XOR solution
>
> > Does anyone know of a reasonably fast way to XOR blocks of data together?
>
> No, but I know of "a" way to perform vanilla XORing, unfortunately a
> "reasonably fast" way to do it alludes me.

[...snip!...]

> > ... I would appreciate it
> > if someone could point me in the right direction.
>
> This is unlikely to be the right direction, but you may find
> my "manual" XORing to be interesting:

[...snip!...]

> on Bitify(n)
> return {n div 128 mod 2 `
> , n div 64 mod 2 `
> , n div 32 mod 2 `
> , n div 16 mod 2 `
> , n div 8 mod 2 `
> , n div 4 mod 2 `
> , n div 2 mod 2 `
> , n mod 2}
> end Bitify

[...snip!...]

> on CharXOR(a, b)
> set o to text item delimiters
> set aa to my Bitify(my AsciiNumber_t(a))
> set bb to my Bitify(my AsciiNumber_t(b))
> set text item delimiters to o
> set cc to my Xorify(aa, bb)
> return my AsciiCharacter(my Numify(cc))
> end CharXOR

I find it more than interesting; I find it mind-boggling. I've printed
it out and will attempt to understand it gradually at my leisure. I
really like the "Bitify" routine which is much simpler than the one I
was playing with to get bytes as bit patterns.

One thing I definitely don't understand at this point is why you use the
"my" preceeding the handler calls. I tried the script with all the
"my"s removed and got the same results. Aren't handler calls always
processed at the script level unless they're in a tell block?

Thanks for the help.

Marc K. Myers <email@hidden>
http://AppleScriptsToGo.com
4020 W.220th St.
Fairview Park, OH 44126
(440) 331-1074

[8/6/02 10:18:36 PM]
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