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Re: Sifting a list sans loop
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Re: Sifting a list sans loop


  • Subject: Re: Sifting a list sans loop
  • From: Kai Edwards <email@hidden>
  • Date: Sun, 27 Jan 2002 09:23:47 +0100

> Date: Sat, 26 Jan 2002 22:55:03 -0600
> From: ehsan saffari <email@hidden>
> Subject: Re: Sifting a list sans loop
> To: AS Users <email@hidden>
>
> A Stoned wizard wrote to me off-list:
>
>> ----------------------------------------------------------------------
>> set l to {"one", "two", "three", "four", {1, 2, 3}}
>>
>> set t to l's text
>> set lst to l's lists
>> ----------------------------------------------------------------------
>
> Paradise!
>
> and similarly one can get a list's dates andd numbers too.

So there I was, playing about with the problem. I tried Akua's 'edit list',
as Paul had suggested - and found that his memory had indeed served him
well. (It doesn't seem to work.)

I also re-checked the ASLG - since I'd vaguely recalled something about the
'whose' filter working with application objects only. The relevant piece (on
page 173) confirmed that 'whose' can't be used to filter AppleScript objects
- such as lists, records or strings.

So - back to the drawing board. After playing around with the syntax for a
while, I was getting ready to give up when - eureka! I'd stumbled upon a
secret, 'magic' formula:

set oldList to {"cat", "dog", {"car", "bus", "tractor"}, "horse", "cow",
{"van"}}
set {newStrings, newLists} to {oldList's strings, oldList's lists}

--> {{"cat", "dog", "horse", "cow"}, {{"car", "bus", "tractor"}, {"van"}}}

Just as I was about to post this wonderful new discovery, I received your
latest message, along with a sprinkling of similar responses - all
suggesting how simple the answer really was.

Yeah - thanks, guys! ;)

(Naturally, I'm still delighted that you got your solution - and I learned
quite a lot from the exercise, too!)

Kai

--

**********************************
Kai Edwards Creative Resources
1 Compton Avenue Brighton UK
Telephone +44 (0)1273 326810
**********************************


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