Re: Number of days left in the month
Re: Number of days left in the month
- Subject: Re: Number of days left in the month
- From: Nigel Garvey <email@hidden>
- Date: Fri, 22 Nov 2002 09:46:13 +0000
I wrote on Fri, 22 Nov 2002 03:21:24 +0000:
>
Emmanuel also wrote on Thu, 21 Nov 2002 22:56:51 +0100:
>
>
>Now the one-liner:
>
>
>
>tell theDate to 32 - (((date ("1 " & its month & " " & its year)) +
>
>31 * days)'s day) returning x
>
>
Or, about twice as fast (on my machines):
>
>
tell (date (theDate's date string)) to 32 - ((it + (32 - (its day)) *
>
days)'s day) returning x
Emmanuel will immediately have spotted (as will Arthur, has, etc.) that
the string's a complete waste of time in my version, so:
tell theDate to 32 - ((it + (32 - (its day)) * days)'s day) returning x
... which is very much faster still. :-)
NG
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