Re: Record sorting routine
Re: Record sorting routine
- Subject: Re: Record sorting routine
- From: Kai <email@hidden>
- Date: Sun, 09 Feb 2003 13:06:56 +0000
on Sat, 8 Feb 2003 13:40:36 -0600, "Jerry Podhajsky" <email@hidden>
wrote:
>
I have a list of records that I'd like to sort by a date field contained
>
in all the records. I'm trying to roll my own with Applescript, but
>
have come up short and very confused.
>
>
Does anyone have a basic Applescript routine (I'm trying to avoid an
>
OSAX, so that I can see the code and maybe learn something) that takes a
>
list of records and sorts them by a specified field in the record?
Try something like this, Jerry:
=======================================
to sortRecords from rList
if rList's length < 2 then return rList
set {l, h, {m, s}} to {{}, {}, rList's {item 1, rest}}
repeat with r in s
if m's d > r's d then
set l's end to r's contents
else
set h's end to r's contents
end if
end repeat
if l's length > 1 then set l to sortRecords from l
if h's length > 1 then set h to sortRecords from h
l & {m} & h
end sortRecords
sortRecords from putYourRecordListHere
=======================================
Depending on how your records are set up, you may need to modify the first
line of the repeat loop (which currently reads: 'if m's d > r's d then').
Firstly, unless the date label in your records just happens to be 'd', then
substitute your own date label.
Secondly, if your dates are entered in a text format (such as "5/3/1995"),
they'll need coercing to a date - so the repeat loop should start with
something like this instead:
=======================================
if date (m's d) > date (r's d) then
=======================================
--
Kai
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