Re: Date math question
Re: Date math question
- Subject: Re: Date math question
- From: Rob Jorgensen <email@hidden>
- Date: Mon, 9 Jun 2003 13:58:10 -0400
At 10:33 AM -0700 6/9/03, Michelle Steiner wrote:
This works:
set foo to "jul 7"
set bar to "jun 26"
set foo to (date foo)
set bar to (date bar)
(foo - bar) / days
This doesn't:
set foo to "jul 7"
set bar to "jun 26"
(date foo) - (date bar)
"(date bar)" is highlighted, with the error as shown below:
--> Can't make date "Thursday, June 26, 2003 12:00:00 AM" into a
number or date.
How come?
I don't know how come but this works:
set foo to "jul 7"
set bar to "jun 26"
((date foo) - (get date bar)) / days
--
Rob Jorgensen
Ohio, USA
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