Re: Concluding that a delimiter was not present in original string
Re: Concluding that a delimiter was not present in original string
- Subject: Re: Concluding that a delimiter was not present in original string
- From: Paul Skinner <email@hidden>
- Date: Tue, 17 Jun 2003 18:16:45 -0400
Your code is reasonable. Although...
if the length of theParts is 1 then
...is, perhaps, more readable.
Paul
On Tuesday, June 17, 2003, at 05:46 PM, Gary Lists wrote:
So sorry for the no subject post.
====
If one is using TIDs to split text chunks, is it a reasonable
conclusion
that if the number of text items returned is 1 then the delimiter was
not
even found in the string?
For example, is this generally reasonable?
set x to "abcde"
set theParts to splitString(x, "5") -- [1]
if number of items of theParts is 1 then
display dialog "That splitter is not found in the string."
else
return theParts -- which would be {"abcde"} if returned
end if
Or is it better to record the original string length, then check the
length
of the first returned item and compare them...if they are equal in
length,
or even the same value, then the split never occurred?
Advice appreciated.
--
Gary
[1]
-- John Delacour's TID handlers
-- see AS-Users List archive at 2003-June-16
-- thread "Why save text item delimiters? Philosophical question...."
on splitString(_string, _cut)
set my text item delimiters to _cut
set ls to text items of _string
set my text item delimiters to ""
return ls
end splitString
MacOS 9.1 / "9 is Fine"
OMM: osa:AS 183 / osa:JS 103 / FM 55 / BB 612 / Smile 188
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