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Re: Get position of item in list
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Re: Get position of item in list


  • Subject: Re: Get position of item in list
  • From: Nigel Garvey <email@hidden>
  • Date: Wed, 25 Jun 2003 23:23:12 +0100

Richard Morton wrote on Wed, 25 Jun 2003 16:33:27 +1000:

>Kai may be aware of this already, but seeing as it's speed we're
>considering, it's perhaps worth noting that assigning multiple values
>in one statement:
>Is slower than doing them separately:

>to getPosition of i from l
> if i is not in l then return 0
> set n to 0
> set o to {}
> set t to text item delimiters
> set text item delimiters to d & d
> set l to d & l & d
> set text item delimiters to d & i & d
> set l to l's text items 1 thru -2
> set text item delimiters to d & d
> repeat with i in l
> set i to i as string
> if i is not "" then set n to n + 1
> tell n + (count i's text items)
> set n to it
> set o's end to it
> end tell
> end repeat
> set text item delimiters to t
> return o
>end getPosition

Don't forget too that counting is faster than string comparisons:

property d : ASCII character 1

to getPosition of i from l
set n to 0
set o to {}
set t to text item delimiters
set text item delimiters to d & d
set l to d & l & d
set text item delimiters to d & i & d
if (count l's text items) = 1 then -- count: 1 text item = not in list
set o to 0
else
set l to l's text items 1 thru -2
set text item delimiters to d & d
repeat with i in l
set i to i as string
if (count i) > 0 then set n to n + 1 -- count: > 0 = not ""
set n to n + (count i's text items)
set o's end to n
end repeat
end if
set text item delimiters to t
return o
end getPosition

NG
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