Re: cost of repeats (was Re: why is applescript so slow???)
Re: cost of repeats (was Re: why is applescript so slow???)
- Subject: Re: cost of repeats (was Re: why is applescript so slow???)
- From: "halloolli" <email@hidden>
- Date: Wed, 1 Dec 2004 15:29:50 +1100
well, sure, it's obvious that counting twice costs more. but in my original
example (which takes more than a minute) i'm counting to 200 (adressbook
cards) not 100000! so, i'd think the main time is spend _inside_ the reapeat
not with handling the repeat loop itself.
olli
----- Original Message -----
From: "Jake Pietrykowski" <email@hidden>
To: "halloolli" <email@hidden>; "wayne melrose"
<email@hidden>; <email@hidden>
Sent: Wednesday, December 01, 2004 1:32 PM
Subject: Re: cost of repeats (was Re: why is applescript so slow???)
It's just logic really...with example (1) you'd be forcing the script to
count twice. Here...try this...got a stopwatch? j/k ;-)
(* start of script *)
set x to 100000
-- Script 1
set counter to 0
repeat with i from 1 to x
set counter to counter + 1
set counter to counter + 1
end repeat
-- Script 2
set counter to 0
repeat with i from 1 to x
set counter to counter + 1
end repeat
repeat with i from 1 to x
set counter to counter + 1
end repeat
(* end of script *)
While BOTH scripts will indeed generate the SAME results...on my PBG4
400mHz...100000 was a high enough number for me to get a 2.5 second count
for script 1 and a 3 second count for script 2. I'd imagine the faster
your
machine, you'd have to keep adding zeros (0) to x so increase the script
run
time.
Placing the REAL TIME test aside...its really just LOGIC. If x =
1,000,000,
why count from zero to 1 million twice? Counting alone takes time...remove
any script action and see the LOGIC.
(1)
repeat with i from 1 to 100
end repeat
OR
(2)
repeat with i from 1 to 100
end repeat
repeat with i from 1 to 100
end repeat
While the script does NOTHING in either case, script 2 must count to a
total
of 200 before complete vs. script 1, a total count of only 100.
Hope this helps...
Kindest Regards,
Jake
On 11/30/04 8:06 PM, "halloolli" <email@hidden> wrote:
From: "wayne melrose" <email@hidden>
After a quick glance at your code, and I mean quick, I would suggest
trying to put your repeats into the same loop..
pardon, so, given the two scripts
(1) repeat with i in theList
do_one_thing
end repeat
repeat with i in theList
do_another_thing
end repeat
and
(2) repeat with i in theList
do_one_thing
do_another_thing
end repeat
does your statement mean that script (1) is substantially slower then
(2)?
well, i might do some tests, but in the meanwhile i want to ask: why does
a
loop itself shall cost so much?
thanks, olli
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