Re: Filters with "entire contents of"
Re: Filters with "entire contents of"
- Subject: Re: Filters with "entire contents of"
- From: Paul Berkowitz <email@hidden>
- Date: Sat, 16 Oct 2004 14:45:28 -0700
On 10/16/04 2:07 PM, "Michelle Steiner" <email@hidden> wrote:
>> The construction is similar to the usual
>>
>> every [element] of [an application object] whose [some property] =
>> [some
>> value]
>>
>>
>> unlike all your other examples, but the application object (entire
>> contents
>> of f) resolves to a list. Here, it's probably implemented as a
>> reference
>> that stays "live" long enough to have a whose clause act on it.
>> Interesting.
>
> But this still doesn't answer the question of why it works with "every
> item of" but doesn't work if that is omitted.
>
> set f to choose folder
> tell application "Finder"
> (entire contents of f) = (every item of entire contents of f)
> end tell
>
> --> true
>
> If they are identical why does the whose clause work with one and not
> the other?
They are not identical. They simply evaluate to the same result.
'every item of', like ALL whose clauses, is constructed as 'every [element]
of [some object]' - which engages the application at some level before any
list is formed. An implementer here will know the lower-level instruction it
uses. 'entire contents', on its own, is evaluated to a list, which can't
support whose clauses. The unusual thing here is that 'every item of entire
contents' seems to be treating 'entire contents' as a reference and not as
an AppleScript list.
--
Paul Berkowitz
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