Re: lists and items and position of items
Re: lists and items and position of items
- Subject: Re: lists and items and position of items
- From: yvan-koenig <email@hidden>
- Date: Fri, 11 Mar 2005 10:48:53 +0100
Le 11 mars 2005 , à 9:50, Christian Vinaa a écrit :
based on Apples example:
on list_position(this_item, this_list)
repeat with i from 1 to the count of this_list
if item i of this_list is this_item then return i
end repeat
return 0
end list_position
set xList to {}
set this_list to {"Sal", "Sue", "Bob", "Carl"}
repeat with x in this_list
set y to list_position(x, this_list)
copy y to end of xList
end repeat
get xList
Hello
You made an error
after "repeat with x in this_list"
x is not a string but a reference to a string.
repeat with x in this_list
set xx to x as text
set y to list_position(xx, this_list)
copy y to end of xList
end repeat
will solve the problem.
Yvan KOENIG
_______________________________________________
Do not post admin requests to the list. They will be ignored.
Applescript-users mailing list (email@hidden)
Help/Unsubscribe/Update your Subscription:
This email sent to email@hidden