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RE: Parsing text from a string
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RE: Parsing text from a string


  • Subject: RE: Parsing text from a string
  • From: "Grimm, Kenneth" <email@hidden>
  • Date: Wed, 16 Mar 2005 21:08:08 -0500

Why does this not work? I thought about just testing to see if the word
started with "[". So first thing was to get words to test, but when I did
this:

set testString to "Have a [nice] [day]"

set Applescript's text item delimiters to space
return words of testString

I get this result:

--> {"Have","a","nice","day"}

I was expecting:

--> {"Have","a","[nice]","[day]"}

What gives? The square brackets are effectively ignored, regardless of tid's
setting. I tried several variations of code, all with same result.

Now I'm all confused...

Ken

> ----------
> From:
> applescript-users-bounces+kgrimm=email@hidden on
> behalf of Marc K. Myers
> Sent: 	Wednesday, March 16, 2005 7:00 PM
> To: 	email@hidden
> Subject: 	Re: Parsing text from a string
>
> On Mar 16, 2005, at 3:01 PM, Todd Geist <email@hidden>
> wrote:
> > Hello again.
> >
> > I am just full of questions today   :>)
> >
> > If I have the string "Have a [Nice] [Day]"
> >
> > I want what is in the first set of brackets "Nice".  The brackets will
> > always be somewhere in the string and I want what is in side of them.
> >
> > Thanks so much for all your help?
>
> set theText to "Have a [Nice] [Day]"
> set {od, AppleScript's text item delimiters} to ¬
> 	{AppleScript's text item delimiters, "]"}
> set x to text items of theText
> set AppleScript's text item delimiters to "["
> set z to ""
> repeat with anItem in x
> 	set y to text items of anItem
> 	if (count of y) > 1 then
> 		set z to last item of y
> 		exit repeat
> 	end if
> end repeat
> set AppleScript's text item delimiters to od
> z
> --> "Nice"
>
> Marc [3/16/05  7:59:36 PM]
>
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