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Re: Days and hours
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Re: Days and hours


  • Subject: Re: Days and hours
  • From: Michelle Steiner <email@hidden>
  • Date: Sun, 16 Oct 2005 13:49:08 -0700

On Oct 16, 2005, at 12:54 PM, Bernard AZANCOT wrote:

I would like to know how to calculate the number of work hours to pay to a person working for me, in a given month, knowing that each

Monday                     -> 2,5 h.
Tuesday                     -> 2,5 h.
Wednesday                -> 2 h.
Friday

This should do it.

set hrs to 0
set working_month to current date
set mon to (choose from list {January, February, March, April, May, June, July, August, September, October, November, December} with title "Employment month" with prompt "Enter the month for which you wish to compute hours worked." default items {month of working_month})
try
set mon to item 1 of mon
on error
error number -128
end try
-- the try block checks for the user clicking cancel.


if mon is less than month of working_month then set year of working_month to (year of working_month) - 1
-- If the month selected is less than the current month, then it was selected for the previous year; adjust the year accordingly.


set month of working_month to mon
repeat with i from 1 to 31
set day of working_month to i
set thisday to weekday of working_month
if month of working_month is not mon then exit repeat
--the only way this will happen is if you go past the number of days in the month; i.e., to the 31st of a 30 day month or to Feb 29th (or Feb 30 of a leap year), so bail out of the loop.


    if thisday is Monday or thisday is Tuesday then
        set hrs to hrs + 2.5
    else if thisday is Friday then
        set hrs to hrs + 2
    end if
end repeat
display dialog hrs

--
Give Peace A Chance.

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  • Follow-Ups:
    • Re: Days and hours
      • From: Bernard Azancot <email@hidden>
    • Re: Days and hours
      • From: "Mark J. Reed" <email@hidden>
References: 
 >Days and hours (From: Bernard AZANCOT <email@hidden>)

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