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Re: Sequential Numbering
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Re: Sequential Numbering


  • Subject: Re: Sequential Numbering
  • From: Justin Middleton <email@hidden>
  • Date: Fri, 16 Sep 2005 12:23:30 -0700

I'm sure there's a better way to do this, but the following will work:

-- replace the rightmost characters of the string
-- representation of inPadding with the string
-- representation of inValue, truncating inValue if
-- necessary.

on rPadInto(inPadding, inValue)
set theStr to ((inPadding as string) & (inValue as string))
return (characters ((length of theStr) - ((length of inPadding) - 1)) thru (length of theStr) of theStr) as string
end rPadInto



Use it thusly:

rPadInto("0000", 120)
>>> "0120"

The string your inserting into can be any string, and doesn't have to be longer than the value you're inserting... if it's not, the value will be truncated on the left.

rPadInto("---", 3225)
>>> "225"

To generate the output you want, do something like this:

-- example usage

set nums to {}
repeat with i from 1 to 1000
    set end of nums to (rPadInto("0000", i))
end repeat

nums
>>> (* a list of 4-digit numbers from 0001 through 1000)

For the sake of brevity, I'm omitting the output... but you get the idea.


Now, can someone show me an easy way to multiply strings in AppleScript, ala python's overloaded multiplication operator, or perl's "string" x numTimes?


/j



On Sep 16, 2005, at 11:36 AM, email@hidden wrote:

Would some one please forward a repeat loop to do  the following:

Make numbers starting with:

0001

 and ending with"

1000

I tried for hours to locate with out success.

Thanks



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