Re: Search for a character
Re: Search for a character
- Subject: Re: Search for a character
- From: pete boardman <email@hidden>
- Date: Mon, 19 Sep 2005 18:25:41 +0100
On 19 Sep 2005, at 16:00, Timothy K. Wilkinson wrote:
I'm having a syntax problem with parsing a text string.
I've parsed a line of text into individual words in a variable.
The word I want is the only one that contains a "%". However I
can't seem to find the right syntax to parse it out.
Since you're using the shell anyway, why not get the information out
in the right format first:
df -h / | grep '%' | cut -f 16 -d ' '
Here, 'cut' is a classic Unix command that cuts bits out of lines of
files. The output of df appears to be space-delimited, so this is
looking for the 16th field. Daft, yes, since it looks more like the
5th field to me, but that was how the old boys used to do it then... :-)
Pete
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