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Re: Shell script to extract time
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Re: Shell script to extract time


  • Subject: Re: Shell script to extract time
  • From: "Adam Bell" <email@hidden>
  • Date: Thu, 6 Apr 2006 12:08:12 -0300

Except that that gives the wrong date and time on my machine.

Wouldn't it be easier to parse out what you wanted from:

do shell script "last reboot"

The first line of that on my machine reads:

reboot    ~                         Wed Apr  5 14:10

On 4/6/06, Mark J. Reed <email@hidden> wrote:
On 4/6/06, Laine Lee <email@hidden> wrote:
On 4/6/06 7:45 AM, "Mark Siple" <email@hidden> wrote:

> do shell script "/usr/sbin/sysctl kern.boottime | awk '{ print $6 }' | sed s/:/./g > " & tPath

Why do you need the sed part?

do shell script "/usr/sbin/sysctl kern.boottime | awk '{ print $6 }' > " & tPath

Uhm, to convert the colons to periods?   Like the OP asked after the  above solution was proposed?

Personally, I recommend a more direct approach.  Given the -n option, sysctl outputs only the value of the variable without the name, and in the case of timestamps, it outputs it in time_t format.  You can feed that to the date command via -r and use the +format option to get it in any form you like:

do shell script "/bin/date -r `/usr/bin/sysctl -n kern.boottime` +'%H.%M.%S' "
 

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Laine Lee


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References: 
 >Re: Shell script to extract time (From: "Laine Lee" <email@hidden>)
 >Re: Shell script to extract time (From: "Mark J. Reed" <email@hidden>)

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