Re: awk question
Re: awk question
- Subject: Re: awk question
- From: Luca Pozzato <email@hidden>
- Date: Fri, 1 Dec 2006 19:59:54 +0100
Hi John, I don’t know AWK, but this is I would do it in Applescript (with Satimage Osax)…
set x to "17 \"Security Update for Exchange 2000 Server (KB894549)\" zeroDotZero application 2005-10-7,13:45:34.0"
set k to every paragraph of (change {"[[:space:]][[:space:]]+"} in x into {"\\r"} with regexp)
Luca
On 01/dic/06, at 19:08, John C. Welch wrote: I'm running into a situation that I've not found a good example for via Google or other sources.
running a script that's designed to process some SNMP output. Awk is a good choice here, and it's being run via do shell script, but I have a twist that's giving me the irrits.
each line has two field delimiters. The most common one is a space. that's easy. The problem is in what I want to be column two, there’s a text string surrounded by double quotes that contains spaces. As an example:
17 "Security Update for Exchange 2000 Server (KB894549)" zeroDotZero application 2005-10-7,13:45:34.0
so I’m trying to get awk to run as “your field delimiters are spaces OR double quotes with any number of any characters or whitespace followed by double quotes”
I can get close, but not close enough to what I want which would be:
$1 = 17
$2 = "Security Update for Exchange 2000 Server (KB894549)"
$3 = zeroDotZero
$4 = application
$5 = 2005-10-7,13:45:34.0
ideas?
|
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| | >awk question (From: "John C. Welch" <email@hidden>) |