Re: awk question
Re: awk question
- Subject: Re: awk question
- From: "Mark J. Reed" <email@hidden>
- Date: Fri, 15 Dec 2006 10:19:13 -0500
On 12/15/06, Martin Orpen <email@hidden> wrote:
Oh, I thought John had already handled the easier awk stuff and it
was the field separators that were problematic?
awk 'BEGIN { OFS="\n" } { print $1, $NF-2, $NF-1, $NF }'
-->
17
2003
2004
2005-10-7,13:45:34.0
You still don't seem to understand the scope of the problem. And
since I know how smart you are, I'm confused by that. :) Am I missing
something?
The goal is to write something that, given this line as input:
17 "Security Update for Exchange 2000 Server (KB894549)"
zeroDotZero application 2005-10-7,13:45:34.0
will produce as output a list of five fields,where the first field is
"17", the second is "Security Update for Exchange 2000 Server
(KB894549)", the third is "zeroDotZero", the fourth is "application",
and the fifth is "2005-10-7,13:45;34.0".
Awk's default column-split behavior won't do that. And if it could,
it wouldn't be needed, because you could do it in AppleScript with
text item delimiters.
There are various ways to code a solution to this problem, but the
simplest seems to me to be to use a regex that matches both quoted and
unquoted fields. So that's what I did. Although my solution doesn't
provide for quotation marks within quoted strings.
--
Mark J. Reed <email@hidden>
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