Apple

hi everyboby,

no loops, just SATIMAGE osax

set found to {" 192.168.1.11", "192.168.1.66"}

set mustHave to {"192.168.1.11", " 192.168.1.66", " 192.168.1.34", "192.168.1.44"}

set Delete_found to change ".+" into "" in found with regexp

set Clean_mustHave to change found into Delete_found in mustHave

set list_to_string to change "(.+)" into "\\1\\r" in Clean_mustHave with regexp

set the_result to find text "(.+)" in list_to_string as text using "\\1" with regexp, all occurrences and string result

-- return {Delete_found, Clean_mustHave, list_to_string, the_result}

return the_result

ciao

Luca Pozzato

On Feb 9, 2006, at 21:54:47, demski wrote:

Hi all,
maybe easy, maybe not?
what I have: two lists
set found to {" 192.168.1.11","192.168.1.66"}
set mustHave to {" 192.168.1.11","192.168.1.66"," 192.168.1.34","192.168.1.44"}

what would be the fastest way to create a list with the missing items like

set missing to {"192.168.1.34"," 192.168.1.44"}

feels like I would ahve to be close to it for its so easy, but...
greetz,

gruss, demski

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References:
	>how to compare two lists without looping? possible? (From: demski <email@hidden>)
	>Re: how to compare two lists without looping? possible? (From: Luca Pozzato <email@hidden>)