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Re: Correcting AGE_INFO
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Re: Correcting AGE_INFO


  • Subject: Re: Correcting AGE_INFO
  • From: Deivy Marck Petrescu <email@hidden>
  • Date: Thu, 4 Feb 2010 11:28:18 -0500


On Feb 4, 2010, at 4:43 AM, Bert Groeneveld wrote:

set D to current date
tell application "Finder"
set M to modification date of alias myFile -- myFile was of course set to some file earlier in the script
end tell
set AGE_INFO to round (D - M) / days rounding up -- is always an integer
set AGE_INFO to correct_AGE_INFO(AGE_INFO, D, M)

on correct_AGE_INFO(AGE_INFO, D, M)
-- what to put here? (as less code as possible, of course)
end correct_AGE_INFO

Hello,
I'm breaking my head about finding some "super algorythm" for this:
I want to correct AGE_INFO, by omitting the days of the weekend (saturday and sunday)
Three possible examples (among many others):
If the weekday of D is thursday and the weekday of M is friday and AGE_INFO is 7, then I want to correct AGE_INFO by -2 (one weekend in between)
If the weekday of D is tuesday and the weekday of M is friday and AGE_INFO is 12, then I want to correct AGE_INFO by -4 (2 weekends)
If the weekday of D is wednesday and the weekday of M is monday and AGE_INFO is 3, then I want to do nothing.

Thanks in advance for any help,

Bert.



Bert, try this but make the corrections for age-info.
Also, it is kind of difficult to consider what would you do if either first or last day is a weekend day.
It is not clear what to consider.


set AGE_INFO to (D - M) div (days)
correct_AGE_INFO(AGE_INFO, D, M)

on correct_AGE_INFO(AGE_INFO, D, M)


set dw to weekday of (M) as integer
set dw1 to weekday of D as integer
set ewend to 0  
if (dw1 - dw) < 0 or (dw1 - dw) = 6 then if dw1 = 1 or dw = 1 then
set ewend to 0.5
else
set ewend to 1
end if
return AGE_INFO - 2 * (AGE_INFO div 7) - 2 * ewend


end correct_AGE_INFO




Deivy Petrescu
email@hidden



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References: 
 >Correcting AGE_INFO (From: Bert Groeneveld <email@hidden>)

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