Ya know, that looks an awful lot like one of the solutions I posted. Just saying. :)
Also you can get rid of the -n and the /p - they cancel each other out in this case.
sed 's/^ *//'
Sed reads in its input a line at a time, runs the given transformations on each line, and prints out the result.
s/^. *// says to substitute the empty string for any number of spaces at the start of the line.
s/old/new/ -> replace first occurrence of "old" on the line with "new"
Old is actually a pattern, not a string; some characters are special:
^ matches the start of the line
space isn't special - it just matches itself
space * matches any number of spaces
Nothing between the middle and last / means the text that matches is replaced with nothing - that is, removed.
Sent from my iPhone
On Jul 28, 2011, at 13:35, "Zavatone, Alex" < email@hidden> wrote: You sir, are a benefit to humanity.
Now, how can I find out why that does what that does?
Any good guides to get started?
Danke. On Jul 25, 2011, at 2:20 PM, Christopher Stone wrote: on trimLeadingWhiteSpace(str) set cmd to "sed -nE 's/^[ ]*//p'<<<" & quoted form of str do shell script cmd return result end trimLeadingWhiteSpace
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