Apple

On Oct 30, 2011, at 11:50 AM, Christopher Stone wrote:

On Oct 30, 2011, at 06:41, Nigel Garvey wrote:
This takes about 0.02 seconds:

repeat with i from 1 to (count theNameList)
set theItem to myname of item i of my theNameList -- NB. 'theNameList' is referenced (with 'my').
set end of my theChooseList to theItem -- Ditto 'theChooseList'.
end repeat
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Hey Nigel,

My, my. That's a whopper of a difference.

0.008 seconds here on my i7 MacBook Pro

Outstanding little trick - any idea of why it works?

Yes. you are pointing to where a value already exists. It's pointer based, instead of incurring the overhead of allocating and duplicating the variable (string therein).

References:
	>Re: Getting record items of a sublist (From: Nigel Garvey <email@hidden>)
	>Re: Getting record items of a sublist (From: Christopher Stone <email@hidden>)