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Re: maths
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Re: maths


  • Subject: Re: maths
  • From: Alex Zavatone <email@hidden>
  • Date: Wed, 18 Apr 2012 16:37:19 -0400

As "integer" is legit.  

Both "as integer" and "as number" should work.

Don't know why "as integer" didn't work.
 
set myVal to "32445" as number
log myVal

(*32445*)

On Apr 18, 2012, at 4:29 PM, Javi Pérez wrote:

Well, it worked in this way:

set topReport to do shell script "top -n1 -l1"
set topCpuUsage to get paragraph 4 of topReport
set userUsage to get word 3 of topCpuUsage
set sysUsage to get word 5 of topCpuUsage
set totalUsage to get word 7 of topCpuUsage as integer
set totalUsage2 to 100 - totalUsage

integer instead number

Enviado con

El miércoles 18 de abril de 2012 a las 22:19, Alex Zavatone escribió:

It's a string.  You got the "word" of a string of text.  That is a string operation.  

You now have to tell it to be a number or AS will børk when trying to subtract a string from a number.

And for those who don't know what "bork" means:
http://www.urbandictionary.com/define.php?term=bork
From:
http://en.wikipedia.org/wiki/Swedish_chef





On Apr 18, 2012, at 3:26 PM, Javi Pérez wrote:




Enviado con

El miércoles 18 de abril de 2012 a las 21:26, Alex Zavatone escribió:

set totalUsage to get word 29 of topReport as number


On Apr 18, 2012, at 3:23 PM, Javi Pérez wrote:

Hello I have this 
set topReport to do shell script "top -n1 -l1"
set totalUsage to get word 29 of topReport

set totalUsage2 to 100 - totalUsage

and I see this 
error "No es posible convertir \"50.0\" en tipo number." number -1700 from "50.0" to number

not possible to convert 50.0 in type number


but it's already a number, I also tried to suffix "as number" in the set totalUsage line, but won't work. If I try manually set totalUsage2 to 100 - 50.2 it works

why?




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References: 
 >maths (From: Javi Pérez <email@hidden>)
 >Re: maths (From: Alex Zavatone <email@hidden>)
 >RE: maths (From: Javi Pérez <email@hidden>)
 >Re: maths (From: Alex Zavatone <email@hidden>)
 >RE: maths (From: Javi Pérez <email@hidden>)

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